When 7 times a number is added to the square of the number, the sum is 3. What is the number?​

Answer:[tex]x\approx -7.405 \text{ or } x \approx 0.405[/tex]Step-by-step explanation:1. Set up the equation   Let x = the number. Then       7x = seven times the number and        x² = the square of the number x² + 7x = seven times the number added to the square of the number x² + 7x = 3 Subtract 3 from each side x² + 7x - 3 = 0 2. Solve the quadratic equation Use the quadratic formula: a = 1; b = 7; c = -3. [tex]x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\=\dfrac{-7\pm\sqrt{(7)^2-4\times1\times(-3)}}{2\times1}\\\\=\dfrac{-7\pm\sqrt{49 + 12}}{2}\\\\=\dfrac{-7\pm\sqrt{61}}{2}\\\\x = \dfrac{-7 - \sqrt{61}}{2} \text{ or } x = \dfrac{-7 + \sqrt{61}}{2}\\\\\mathbf{x\approx -7.405} \text{ or } \mathbf{x \approx 0.405}[/tex]The graph of your quadratic crosses the x-axis at (-7.405,0) and (0.405,0).