Find the vertices and foci of the hyperbola with equation quantity x plus 4 squared divided by 9 minus the quantity of y minus 5 squared divided by 16 = 1

Answer:Vertices at (-7, 5) and (-1, 5). Foci at (-9, 5) and (1,5). Step-by-step explanation:(x + 4)²/9 - (y - 5)²/16 = 1 The standard form for the equation of a hyperbola with centre (h, k) is (x - h²)/a² - (y - k)²/b² = 1 Your hyperbola opens left/right, because it is of the form x - y. Comparing terms, we find that h = -4, k = 5, a = 3, y = 4 In the general equation, the coordinates of the vertices are at (h ± a, k). Thus, the vertices of your parabola are at (-7, 5) and (-1, 5). The foci are at a distance c from the centre, with coordinates (h ± c, k), where c² = a² + b². c² = 9 + 16 = 25, so c = 5. The coordinates of the foci are (-9, 5) and (1, 5). The Figure below shows the graph of the hyperbola with its vertices and foci.