A flower bed is in the shape of a triangle with one side twice the length of the shortest side, and the third side is 14 feet more than the length of the shortest side. Find the dimensions if the perimeter is 146 feet.
Accepted Solution
A:
Answer:The dimensions of triangle are 66 ft, 33 ft and 47 ftStep-by-step explanation:Letx -----> the length of one sidey -----> the length of the shortest sidez -----> the length of the third sidewe know thatThe perimeter of triangle is[tex]P=x+y+z[/tex][tex]P=146\ ft[/tex]so[tex]146=x+y+z[/tex] -----> equation A[tex]x=2y[/tex] -----> equation B[tex]z=y+14[/tex] ----> equation CSubstitute equation B and C in equation A and solve for y[tex]146=2y+y+y+14[/tex][tex]146=4y+14[/tex][tex]4y=146-14[/tex][tex]4y=132[/tex][tex]y=33\ ft[/tex]Find the value of x[tex]x=2(33)=66\ ft[/tex] Find the value of z[tex]z=33+14=47\ ft[/tex] thereforeThe dimensions of triangle are 66 ft, 33 ft and 47 ft